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If you place 3.020 g of SrCO3 in a beaker containing 0.5 M of sodium carbonate,...

If you place 3.020 g of SrCO3 in a beaker containing 0.5 M of sodium carbonate, what will be the cation concentration at equilibrium?

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Answer #1

Solutions 3.020g of SCO3 + 0.5m Sodium Carbonate . (Na2CO3) Molar mass of Sr CO₂- 147.68 Mole of 3.020 g of SCO3 = 3.020 147.

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