Given your own results and the data provided, a partial mechanism for the reaction may be proposed as:
MnO4- +C6H5CH2OH + H+ = an intermediate
Write a sentence to explain why such a mechanism is flawed? and a proposal of a better mechanism?
Solution:
MnO4- + C6H5CH2OH + H+ = intermediate
The given mechanism is considered as flawed because trimolecular collisions are not realistic, it occurs rarely.
The balanced equation for the reaction of MnO4- with benzyl alcohol in acidic medium will be:
4MnO4- + 12 H+ + 5C6H5CH2OH = 5C6H5COOH + 4 Mn2+ 11 H2O
Thus, reaction is a type of redox reaction in which KMnO4- is reduced to Mn2+ and C6H5CH2OH is oxidized into C6H5COOH.
KMnO4 = Mn2+ ( reduction)
C6H5CH2OH = C6H5COOH (oxidation)
Given your own results and the data provided, a partial mechanism for the reaction may be...
Two people proposed mechanisms for this reaction. One proposed mechanism for the reaction is: CH3COCH3 + Br2 CH3COCH2Br + H+ + Br- The other proposed mechanism for the reaction is: CH3COCH3 + H+ CH3COHCH2+ CH3COHCH2+ + Br2 CH3COCH2Br + HBr Based on the data collected in the above problem, which mechanism is supported as most likely correct? Explain your reasoning. Determine the limiting reagent for the above reaction(52) Determine the rate constant for the first reaction above.(52)
Assignment 6: Mechanism Correction On a page titled Incorrect Mechanism print the incorrect mechanism provided for your molecule on Blackboard. For the mechanism you will focus on the reaction of the portion of the molecule drawn only (not the R part). The molecule will be drawn with R groups so that you may ignore other reactive parts of the molecule. In fact, it is essential that the R groups are ignored even if they may have an effect on the...
Assignment 6: Mechanism Correction On a page titled Incorrect Mechanism print the incorrect mechanism provided for your molecule on Blackboard. For the mechanism you will focus on the reaction of the portion of the molecule drawn only (not the R part). The molecule will be drawn with R groups so that you may ignore other reactive parts of the molecule. In fact, it is essential that the R groups are ignored even if they may have an effect on the...
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Q4a - The reaction of butan-2-ol with concentrated aqueous HBr goes with partial racemization, giving more inversion than retention of configuration. Propose a mechanism that accounts for partial inversion. Draw all the arrows to indicate movement of electrons, write all lone pairs involved into electron transfer, all formal charges, and all the products for each step. If a racemic mixture is formed, you may indicate this using a wavy line www or mark the chiral center with an asterisk (*),...
11b) Draw a curved arrow mechanism for the following reaction. Your mechanism should explain BOTH products HO £ * a OPP c) The product of part B does not follow Zaitsev's Rule. Explain (1 sentence) why in this particular Tatooinian biochemical system the less crowded product could be the major product.
Given the information below, write out a reasonable mechanism
for the reaction. where not provided also fill in the major product
of the reaction
B' (strong base) Doubling [B'] doubles rate of rxn. H2O 「 一 SN1
Use the provided thermodynamic data at 298 K and partial pressures given to decide in which direction (forward or backward) the reaction will proceed under these conditions: Compound ΔG (kJ/mol) Partial Pressure (atm) SO2 (g) -300.2 1.0 x 10-4 O2 (g) 0.0 0.20 SO3 (g) -371.1 0.10
help please
Incorrect Mechanism (The mechanism is for the formation of the 1,4 product. Please ignore the 1,2 product). + Br + H-Br R Br Assignment 6: Mechanism Correction On a page titled Incorrect Mechanism print the incorrect mechanism provided for your molecule on Blackboard. For the mechanism you will focus on the reaction of the portion of the molecule drawn only (not the R part). The molecule will be drawn with R groups so that you may ignore other...
my
molecule is 2,6-dimethyloct-2-ene
Assignment 6: Mechanism Correction On a page titled Incorrect Mechanism print the incorrect mechanism provided for your molecule on Blackboard. For the mechanism you will focus on the reaction of the portion of the molecule drawn only (not the R part). The molecule will be drawn with R groups so that you may ignore other reactive parts of the molecule. In fact, it is essential that the R groups are ignored even if they may have...