Question

What is the electric field at point 1 in (Figure 1)? Assume that a= 3.0 cm and b = 4.0 cm.

一10 nC

What is the electric field at point 2 in (Figure 1)?

What is the electric field at point 3 in (Figure 1)?

Answer 1

The electric field Due to point charge at distance x E = k q/x^2 if q is positive if q is negative Where k = 8.99 times 10^+ 9 N-m^2/c^2 r_1 = a = 3 cm = 0.03m From Pythagoras Theorem (r_2)^2 = a^2 + b^2 = (3)^2 + (4)^2 = 25 cm^2 r_2 = 5 cm = 0.05 m r_3 = b = 4 cm = 0.04 m q = 10 nc = 10 times 10^-9 c The magnetic of electric: At point 1 E_1 = kq/(r_1)^2 = 8.99 times 10^9 times 10 times 10^-9/(0.03)^2 = 99888.89 N/C At point 2: E_2 = k q/(r_2)^2 = 8.99 times 10^9 times 10 times 10^-9/(0.05)^2 = 35960 N/C At point 3: E_3 = K q/(r_3)^2 = 8.99 times 10^9 times 10 times 10^-9/(0.04)^2 = 56187.5 N/C tan theta = a/b = 3/4 = > theta = tan^-1 (3/4) = 36.87 degree Let i^Hat, j^Hat
In vector form:-