Question

10

Question 10 Tries remaining: 1 Points out of 1,00 P Flag question What is the pH of a 10.1 M solution of H2SO4? The first proton completely dissociates; the Ka for the second proton is 1.2x10-2 Answers must be accurate to 2 decimal places. Multiple tries are permitted; however, 20% (1/5) point will be deducted for each incorrect response Answer: -1.00 Assume that the concentration of [H2SO4) = [HSO ). Make an ICE table for the second deprotonation Try again

Answer 1

Dissociation of H2804 H2 504 + H+ +4504 Since first proton completely dissociate so H₂504 = 10.1M H2504 -> H+ +H504 10.1m 10.1M 10.1M [H] - [H504 ] = 10.1 M Now second dissociation Hoa HT +504 Kg = 12x102 10.1M 10.1m preparing ICE Table for second step HSO4 ² H+ + soo²- inisial 10.1 10:1 te ta change -X 1o.lt At quilibrium 1001-2

K92= [+] [soq) (4504] 1.2X1032 -(613C) () (10:1-2) 1:2x10-2 10.12 + x2 1. 10.12 12012x10-2 – 1.2816-3x = 10:12+x? x? +10.112-1212x10220 Compare it with ax²+bxtc o b= a=1 10.112 C= -1 2:12 X 10-2 -b I J 6²-496 2a - 10.112 I s lo.112)-4X1X-12'12X10 = 2 - 10-112- - 1 J102.737 = 2 0.0119 [509?) = x = 0.0119 = 0.012 0.01g +10.1 = lote 10.112 [HP]= x+ 10:1 bu= -log [ht] = -log(10.1990 $4 = 1.00 fry