Question

A solution containing 3.57mg/100ml of A (225g/mol) has a transmission of 66% in am 1.00cm cell at 392 nm. Calculate its absorptivity.

Answer 1

PAGE: DATE: 1 Answer → We have to calculate absorptivity a'. It is defined as the ratio of the absorbance to the product of the length of Opticou path 'b' and the concentration of the sample ic', ! TE is given by the formwa Absorbance path length bc x concentration centimeter Here, Path length is always defined in and concentration in grams leiter Step 1 we have to concwate absorbance from transmittance Given, YT = 66 y. T 66 = 0.66 100 From the defination of absorbance we have __A = logto = -log, T

PAGE: DATE: 1 A = 0.1804 → Absorbance 'A' = 0.1804 Step 1: We have to caucwote absorptivity by using equdtion () a A Here, A= 0.1804 b = cm c. 3.57 mg 100 ml 3.57 x1039 100X10-3L 2. C 0.0 357 9/L .' 0:1804 1 X 0.0357 a = 5:053 lit gram'cmi! → Absorptivity of the solution is 5.053 lit gram
Therfore the absorptivity of the solution is 5.053 lit gram^-1 cm^-1.