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For an LRC series circuit containing a resistance of 15 k2, a capacitance of 6 uF, and an inductance of 25 H, what frequency

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Answer #1

For series LRC circuit, when series resonance occurs, the impedance will be minimum.

Given that -

R = 15 k\Omega = 15000 \Omega

C = 6 uF = 6 x 10^-6 F

L = 25 H

Expression for the resonance frequency is -

fr = 1 / [(2*pi)*sqrt(LC)]

= 1 / [(2*3.141)*sqrt(LC)]

= 1 / [(2*3.141)*sqrt(25 x 6 x 10^-6)]

= 10^3 / (2 * 3.141 * 12.25) = 13.0 Hz = 1.3 x 10^-2 kHz

Hence, third option is the correct answer.

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