For series LRC circuit, when series resonance occurs, the impedance will be minimum.
Given that -
R = 15 k
= 15000
C = 6 uF = 6 x 10^-6 F
L = 25 H
Expression for the resonance frequency is -
fr = 1 / [(2*pi)*sqrt(LC)]
= 1 / [(2*3.141)*sqrt(LC)]
= 1 / [(2*3.141)*sqrt(25 x 6 x 10^-6)]
= 10^3 / (2 * 3.141 * 12.25) = 13.0 Hz = 1.3 x 10^-2 kHz
Hence, third option is the correct answer.
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