pH of buffer acidic bufferis given by, pH = pka + log(conjugate base/acid)
pKa of Formic acid = 3.74
pH = 3.74 +log(0.10/0.15)
= 3.56
NaCHO2 component of the buffer must be added to change the pH from 3.56 to 3.91
Let x be mmoles of NaCHO2 added, then
pH of buffer = pka + pka + log(conjugate base+x/acid)
3.91= 3.74 + log((25+x)/37.5)
Number of mmoles of X(NaCHO2) must be added = 30.47
mass of X(NaCHO2) must be added = 30.47*68/1000 = 2.072 gms
a 250.0 ml buffer solution initially contains 0.15 M HCHO2 and 0.10 M NaCHO2. what is...
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