The activation energy of a certain reaction is 44.3 kJ/mol . At 30 ∘C , the rate constant is 0.0180s−1 . At what temperature in degrees Celsius would this reaction go twice as fast?
Express your answer with the appropriate units.
I'm so confused... When I worked this problem I got 317.67 K, or 44.67 C, but they're both wrong. What am I doing wrong?

The activation energy of a certain reaction is 44.3 kJ/mol . At 30 ∘C , the...
The activation energy of a certain reaction is 37.3 kJ/molkJ/mol . At 30 ∘C ∘C , the rate constant is 0.0190s−10.0190s−1 . At what temperature in degrees Celsius would this reaction go twice as fast? Express your answer with the appropriate units.
The activation energy of a certain reaction is 30.1 kJ/mol . At 28 ∘C , the rate constant is 0.0120s−1 . At what temperature in degrees Celsius would this reaction go twice as fast? Express your answer with the appropriate units.
The activation energy of a certain reaction is 35.5 kJ/mol . At 21 ∘C , the rate constant is 0.0110s−1. At what temperature in degrees Celsius would this reaction go twice as fast?
The activation energy of a certain reaction is 30.1 kJ/mol . At 28 ∘C , the rate constant is 0.0120s−1 . At what temperature in degrees Celsius would this reaction go twice as fast?
The activation energy of a certain reaction is 49.8 kJ/mol . At 23 ∘C , the rate constant is 0.0140s−1. At what temperature in degrees Celsius would this reaction go twice as fast?
Given that the initial rate constant is 0.0180s−1 at an initial temperature of 30 ∘C , what would the rate constant be at a temperature of 180. ∘C for the same reaction described in Part A? Express your answer with the appropriate units. (I solved this and got 2.01, which is wrong, but I'm not exactly sure why). (Reaction A was: The activation energy of a certain reaction is 44.3 kJ/mol . At 30 ∘C , the rate constant is...
The activation energy of a certain reaction is 49.2 kJ/molkJ/mol . At 26 ∘C ∘C , the rate constant is 0.0150s−10.0150s−1 . At what temperature in degrees Celsius would this reaction go twice as fast?
PART A The activation energy of a certain reaction is 30.7 kJ/mol . At 20 ∘C, the rate constant is 0.0130 s−1. At what temperature would this reaction go twice as fast? Express your answer numerically in degrees Celsius Part B Given that the initial rate constant is 0.0130 s−1 at an initial temperature of 20 ∘C, what would the rate constant be at a temperature of 100 ∘C? Express your answer numerically in inverse seconds.
Part . A The activation energy of a certain reaction is 38.7 kJ/mol . At 28 ∘C , the rate constant is 0.0170s−1. At what temperature in degrees Celsius would this reaction go twice as fast? Express your answer with the appropriate units. Part B Given that the initial rate constant is 0.0170s−1 at an initial temperature of 28 ∘C , what would the rate constant be at a temperature of 110. ∘C for the same reaction described in Part A?Part Express your...
A: The activation energy of a certain reaction is 36.8 kJ/mol . At 27 ∘C , the rate constant is 0.0120s−1. At what temperature in degrees Celsius would this reaction go twice as fast? B: Given that the initial rate constant is 0.0120s−1 at an initial temperature of 27 ∘C , what would the rate constant be at a temperature of 100. ∘C for the same reaction described in Part A?