The activation energy of a certain reaction is 37.3 kJ/molkJ/mol . At 30 ∘C ∘C , the rate constant is 0.0190s−10.0190s−1 . At what temperature in degrees Celsius would this reaction go twice as fast?
Express your answer with the appropriate units.
The activation energy of a certain reaction is 37.3 kJ/molkJ/mol . At 30 ∘C ∘C ,...
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The activation energy of a certain reaction is 37.3 kJ/mol . At 20 °C, the rate constant is 0.0120s-. At what temperature in degrees Celsius would this reaction go twice as fast? Express your answer with the appropriate units. View Available Hint(s) μΑ Submit Previous Answers Part B Given that the initial rate constant is 0.0120s at an initial temperature of 20 °C, what would the rate constant be at a temperature of 120. °C for...
The activation energy of a certain reaction is 47.9 kJ/molkJ/mol . At 29 ∘C ∘C , the rate constant is 0.0180s−10.0180s−1 . At what temperature in degrees Celsius would this reaction go twice as fast? Express your answer with the appropriate units. T2= Given that the initial rate constant is 0.0180s−10.0180s−1 at an initial temperature of 29 ∘C ∘C , what would the rate constant be at a temperature of 170. ∘C ∘C for the same reaction described in Part A? k2=
The activation energy of a certain reaction is 30.1 kJ/mol . At 28 ∘C , the rate constant is 0.0120s−1 . At what temperature in degrees Celsius would this reaction go twice as fast? Express your answer with the appropriate units.
The activation energy of a certain reaction is 49.2 kJ/molkJ/mol . At 26 ∘C ∘C , the rate constant is 0.0150s−10.0150s−1 . At what temperature in degrees Celsius would this reaction go twice as fast?
The activation energy of a certain reaction is 44.3 kJ/mol . At 30 ∘C , the rate constant is 0.0180s−1 . At what temperature in degrees Celsius would this reaction go twice as fast? Express your answer with the appropriate units. I'm so confused... When I worked this problem I got 317.67 K, or 44.67 C, but they're both wrong. What am I doing wrong?
Part . A The activation energy of a certain reaction is 38.7 kJ/mol . At 28 ∘C , the rate constant is 0.0170s−1. At what temperature in degrees Celsius would this reaction go twice as fast? Express your answer with the appropriate units. Part B Given that the initial rate constant is 0.0170s−1 at an initial temperature of 28 ∘C , what would the rate constant be at a temperature of 110. ∘C for the same reaction described in Part A?Part Express your...
Part A The activation energy of a certain reaction is 30.9 kJ/mol . At 29 ∘C , the rate constant is 0.0170s−1 . At what temperature in degrees Celsius would this reaction go twice as fast? Express your answer with the appropriate units. View Available Hint(s) T2 = Part B Given that the initial rate constant is 0.0170s−1 at an initial temperature of 29 ∘C , what would the rate constant be at a temperature of 100. ∘C for the...
Part A) The activation energy of a certain reaction is 33.9 kJ/mol . At 20 ∘ C , the rate constant is 0.0160 s −1 . At what temperature in degrees Celsius would this reaction go twice as fast? Express your answer with the appropriate units. Answer was: T 2 = 35 ∘ C Part B Given that the initial rate constant is 0.0160 s −1 at an initial temperature of 20 ∘ C , what would the rate constant...
PART A The activation energy of a certain reaction is 30.7 kJ/mol . At 20 ∘C, the rate constant is 0.0130 s−1. At what temperature would this reaction go twice as fast? Express your answer numerically in degrees Celsius Part B Given that the initial rate constant is 0.0130 s−1 at an initial temperature of 20 ∘C, what would the rate constant be at a temperature of 100 ∘C? Express your answer numerically in inverse seconds.
The activation energy of a certain reaction is 35.5 kJ/mol . At 21 ∘C , the rate constant is 0.0110s−1. At what temperature in degrees Celsius would this reaction go twice as fast?