Be sure to answer all parts. Calculate the pH of a solution that is: 1.6 x...

Question

Question

science chemistry

Answer 1

Answer #1

_PH= -log[H⁺]

HCl_(aq) -------> H⁺_(aq) + Cl^-_(aq)

Given: [H⁺] = 1.6 x 10^-2M

_PH= -log[H⁺] = -log[1.6 x 10^-2] = -log(1.6) - log(10^-2) [since , log(axb) = loga + logb and loga^b = b loga]

=-0.204-(-2log10) [ log10=1]

_PH =2-0.204= 1.795

Answer 2

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