Question

1. A person lowers a bucket into a well by tuming a hand crank, as the drawing illustrates The crank handle moves with a constant tangential speed of 1.20 m/s on its circular path. Find the linear speed with which the bucket moves down the well. 0,400 m diameter V120 m/s

Answer 1

Diameter of the hand crank, d = 0.40 m

So, circumference of the handle's arc = π * d = 3.141 * 0.40 m = 1.26 m ( one revolution)

Tangential speed of crank handle, v = 1.20 m/s

So, angular velocity of the crank handle = 1.2 m/s / 1.26 m/rev = 0.952 rev/s

The same rate applies to the inner part, but there the circumference is 0.1π = 0.314 m (per rev)

Therefore, linear speed with which the bucket moves down the well = 0.314 m/rev x 0.952 rev/s = 0.30 m/s (Answer).