
Page 2 Rotational Motion Questions The formula for the moment of inertia of our disk rotating...
The moment of inertia of a disk rotating about its axis of symmetry is Icm=1/2MR^2 The formula for finding the moment of inertia of an object rotating off axis if its on axis center of mass moment of inertia is I=Icm + Md^2 Given a disk 10cm in diameter whose mass is 1500g, find its off-axis moment of inertia if the disk is located 10cm from the axis rotation.
E17. A uniform disk with a mass of 7 kg and a radius of 0.4 m is rotating with a rotational velocity of 15 rad/s. a. What is the rotational inertia of the disk? (See fig. 8.15.) b. What is the angular momentum of the disk?
E17. A uniform disk with a mass of 7 kg and a radius of 0.4 m is rotating with a rotational velocity of 15 rad/s. a. What is the rotational inertia of the disk?...
A uniform disk with mass M and radius R is rotating about an axis through its center-of-mass. The axis is perpendicular to the disk. The moment of inertial for the disk with a central axis is I MR2. Two non-rotating smaller disks, each with mass M2 and radius R/4, are glued on the original disk as shown in the figure. (a) Show that the ratio of the moments of inertia is given by I'/I = 35/16, where I' is the moment...
Consider a turntable to be a circular disk of moment of inertia 0.142 kg⋅m2 rotating at a constant angular velocity 4.80 rad/s2 around an axis through the center and perpendicular to the plane of the disk (the disk's "primary axis of symmetry"). The axis of the disk is vertical and the disk is supported by frictionless bearings. The motor of the turntable is off, so there is no external torque being applied to the axis. Another disk (a record) is...
st Semester, Year 2019 (9) Formula 1= MR2( 1 should be modified formula for the thed if the pulley as well as the object in the rotation instrument rotates. Derive the rotating pulley with the rotational inertia I, r, regarding the pulley as a circular plate with the mass m andthe radius·«S ports
st Semester, Year 2019 (9) Formula 1= MR2( 1 should be modified formula for the thed if the pulley as well as the object in the rotation...
Find the uncertainty in the moment of inertia. Moment of interia of a disk depends on mass and radius according to this function I(m,r) = 1/2 m r2. Your measured mass and radius have the following uncertainties delta m space equals space 0.43 kg and delta r space equals space 0.11 m. What is is the uncertainty in moment of interia, delta I , if the measured mass, m = 6.43 kg and the measured radius, r = 10.14 m?
A disc of moment of inertia 3.00 kgm2 is rotating with angular velocity 2.00 rad/s about an axis perpendicular to its plane and passing through its centre. Another disk (which is not rotating) of moment of inertia 5.00 kgm2 is gently placed over it. Finally, the two discs rotate with the same angular velocity around the common rotational axis. The new angular velocity of the combined disc (in rad/s) is ?
a. The moment of inertia of the reaction wheels has a value RI and the moment of inertia of the telescope about its symmetry axis, and about an axis perpendicular to its symmetry axis is represented by Iz and Ix , respectively. Find an expression for the final speed of the appropriate reaction wheel wRf to cause the telescope to change its direction at a rate of wt for a nominal (i.e. idling) rotational speed of the flywheels of wRi...
What is the moment of inertia of a disk 6.9 meters in radius of mass 92.51 kg rotating about its center? Give your answer in kg-m2.
Question 3 10 pts A horizontal disk with moment of inertia 0.36 kg-m2 is rotating with an angular speed of 6.5 rad/sec. A point mass of 0.52 kg is gently placed on the outer edge of the disk in a manner so that no torque is applied. The mass then rotates with the disk at an angular speed of 4.37 rad/sec. What is the radius of the disk in meters? 0.38 0.28 0.88 0.58