Question

CI 3. For the reaction: 3 TiO2 +4 Al 2 Al O3 + 3 Ti (a) If you have 100 grams of Tio, and 50. grams of Al, which is the limiting reactant? How much Ti will be produced? QAL mal Al (b) What is the percentage yield if the yield of Ti is 52 g? 4. Limiting reactants can control whether any of the reactants are left over in a reaction. This may be very important. For example, for the synthesis of HBr gas, we have the reaction: 2 Br2+C10H10 2 HBr + CioHgBr2 (a) The presence of leftover CloHjo is no problem, but leftover Bry can be a big problem. Which reactant should be in excess? (b) If you have a mixture of 0.250 g of Cioto and 1.00 g of Br2, are you doing the reaction in a safe manner? (c) What is the actual yield if the percentage yield is 75%? 80

Answer 1

125 mo 3) 3 TiO2+ + Al - 2 ALO3 + 37: a) moles of Tio2 = 100 ) 1125 moles, moles of Al= ora 1.85 moles ;) 3 moles of Tiog gives Brodes of Ti - 1.25 moles of Tiog gives 3xl-25 123 ii) 4 moles of Al gives a 3 moles of Ti 185 moles of Al gives - 3x1.85 1.387 mdes of li Tio is the limeting reagente as it gives the less moles of Ti. moles of the formed = 1,25 moles mans of Ti formed a molestrolarnas (Ti= 41.87 g/mol) 31:25% 49.87 €59.849 b) percent yield = actual yield , wo Theoretical yield 52 X100 59584 = 86.89./.

A) 2. Br +Golio 2 HBr + cio Hq Biz a) Bromine is corrosine to human timue if it is liquid form and very toxic and we have to use this Bra liquid in aqueous fason like Bromine water. moles of Brg= man a 100 0.00626 moles molarmou 159.8 130 moles of cloto = 0.250 > 0.00192 moes :) 2 moles of Brg gives 2 moles of HB 0.00626 moles of Bre gives 2x0100626 0.00626 moles of HBY. 1) I mole of Gothio gives 2 moles of HB 0.00192 moles of clothio gives 240100192 0.00384 modes of HB * Cohio is the limiting reagent. * Brg is the excers reagent. b) Bry is the excess reagent, so, we are not doing the reaction - in a safe manner because excers Bry will causes harmfull - to body. Theoretical yield of HBr = molestmdaman 0.00384*80.9 --> 0131069 I actual yield x 100 c) percent yield Theoretical field 75 = actual yield --x100 0.3106 Actualyield= 75*0.3106 100 = 0.2329 g