In a test of a new reference electrode, a chemist constructs a voltaic cell consisting of...

Question

Question

science chemistry

Answer 1

Answer #1

Zn Oxd ha Gl +9e a ae ed nal Gl re H2 Eoxd Ened Eal = -0.16 + - (o- .F6 Eal E-RT In 6.04 S.314 x a8 3-303 &x96500 - -076-0 02

Answer 2

Similar Homework Help Questions

In a test of a new reference electrode, a chemist constructs a voltaic cell consisting of...

In a test of a new reference electrode, a chemist constructs a voltaic cell consisting of a Zn/Zn2+ half-cell and an H2/H+ half-cell under the following conditions: [Zn2+ ] = 0.021 M [H+ ]= 1.3 M partial pressure of H2 = 0.32 atm. Calculate Ecell at 298 K (enter to 3 decimal places). Zn2+ (aq) + 2e − ⟶ Zn(s) E° = − 0.76 V 2H+ (aq) + 2e − ⟶ H2(g) E° = 0.00 V We were unable...
Consider a voltaic cell al 25 degree Celsius in which the reaction is: Zn (s) +...

Consider a voltaic cell al 25 degree Celsius in which the reaction is: Zn (s) + 2H+ (aq) → Zn2+ (aq) + H2(g) It is found that the voltage (think Ecell) is +0.560 V when [Zn2+1 -0.85 M and PH2 = = 0.988 atm. What is the pH in the H2-H half-cell?
The standard cell potential (E°) of a voltaic cell constructed using the cell reaction below is...

The standard cell potential (E°) of a voltaic cell constructed using the cell reaction below is 0.76 V: Zn(s) + 2H+(aq) → Zn2+(aq) + H2(g) With PH2= 1.0 atm and [Zn2+] = 1.0 mol L-1, the cell potential is 0.37 V. The concentration of H+ in the cathode compartment is ________ mol L-1. Answers: 2.6 × 10-7 5.1 × 10-4 0.686.6 × 10-14 4.3 × 10-27

The standard cell potential (E°) of a voltaic cell constructed using the cell reaction below is...

The standard cell potential (E°) of a voltaic cell constructed using the cell reaction below is 0.76 V: Zn (s) + 2H+ (aq) → Zn2+ (aq) + H2 (g) With PH2 = 1.0 atm and [Zn2+] = 1.0 M, the cell potential is 0.42 V. The concentration of H+ in the cathode compartment is ________ M. please explain the math Thank you
a.) A voltaic cell is constructed in which the cathode is a standard hydrogen electrode and...

a.) A voltaic cell is constructed in which the cathode is a standard hydrogen electrode and the anode is a hydrogen electrode (P(H2) = 1 atm) immersed in a solution of unknown [H+]. If the cell potential is 0.204 V, what is the pH of the unknown solution at 298 K? b.) An electrochemical cell is constructed in which a Cr3+(1.00 M)|Cr(s) half-cell is connected to an H3O+(aq)|H2(1 atm) half-cell with unknown H3O+ concentration. The measured cell voltage is 0.366...
Draw the voltaic cell that will give the most positive cell potential choosing from the following...

Draw the voltaic cell that will give the most positive cell potential choosing from the following half reactions: Eo (vs. SHE) Zn2+ (aq) + 2e- Zn (s), Eo= -0.76 Al3+ (aq) + 3e- Al (s), Eo= -1.66 Cr3+ (aq) + 3e- Cr (s), Eo= -0.74 Co2+ (aq) + 2e- Co (s), Eo= -0.28

Design a voltaic cell with the following two reduction half -reactions : Design a voltaic cell...

Design a voltaic cell with the following two reduction half -reactions : Design a voltaic cell with the following two reduction half-reactions Ag+(aq) + e-→ Ag(s) Zn2+(aq) + 2 e-→Zn(s) E 0.80 V Eo = 0.76 V Calculate Eocell and the equilibrium constant K for th copy of Final Exam cover sheet. e voltaic cell at 298 K. Click here for a E° cell -0.04 V and K-4.7 E cell-0.04 V and K-0.21 O Eocel =-0.04 V and K =...
A voltaic cell is set up with one beaker containing 1.0 M Zn(NO 3) 2 and...

A voltaic cell is set up with one beaker containing 1.0 M Zn(NO 3) 2 and a zinc electrode, and another beaker containing 1.0 M Ni(NO 3) 2 and a nickel electrode. Given the following standard reduction potentials, answer the 3 questions below: Eº Zn2+(aq) + 2e → Zn(s) -0.76 V Ni2+(aq) + 2e → Ni(s) -0.23V Part a. Write out the half-cell reaction that occurs at the anode of the voltaic cell. Part b. In which direction do...
calculate ecell for the following electrochemical cell at 25 C. Pt(s)| H2 (g,1.00 atm) | H+...

calculate ecell for the following electrochemical cell at 25 C. Pt(s)| H2 (g,1.00 atm) | H+ (aq, 1.00 M) || (Pb2+ (aq, 0.150 M) | Pb (s) Pb^2+(aq) + 2e- ---> Pb (s) Eo=-0.126 V 2H^+ (aq) + 2e- ---> H2 (g) Eo=0.00 V Thank you!

Separate galvanic cells are made from the following half-cells: cell 1: H+(aq)/H2(g) and Pb2+(aq)/Pb(s) cell 2:...

Separate galvanic cells are made from the following half-cells: cell 1: H+(aq)/H2(g) and Pb2+(aq)/Pb(s) cell 2: Fe2+(aq)/Fe(s) and Zn2+(aq)/Zn(s) Which of the following is correct for the working cells? Standard reduction potentials, 298 K, Aqueous Solution (pH = 0): Cl2(g) + 2e --> 2C1-(aq); E° = +1.36 V Fe3+(aq) + e --> Fe2+(aq); E° = +0.77 V Cu2+(aq) + 2e --> Cu(s); E° = +0.34 V 2H+(aq) + 2e --> H2(g); E° = 0.00 V Pb2+(aq) + 2e --> Pb(s);...