Actual yield of Fe = 22.7 g
Use:
% yield = actual yield * 100 / theoretical yield
93.2 = 22.7 * 100 / theoretical yield
theoretical yield = 24.36 g
Molar mass of Fe = 55.85 g/mol
mass of Fe = 24.36 g
mol of Fe = (mass)/(molar mass)
= 24.36/55.85
= 0.4362 mol
According to balanced equation
mol of Al required = moles of Fe
= 0.4362 mol
Molar mass of Al = 26.98 g/mol
mass of Al = number of mol * molar mass
= 0.4362*26.98
= 11.8 g
Answer: C
2. Consider the balanced Thermite reaction below, which has a reaction yield of 93.2%. If you're...
In the thermite reaction, iron (III) oxide is reduced by aluminum to give molten iron, Fe2O3 (s) + 2 Al (s) --> 2 Fe (l) + Al2O3 (s) If you begin with 10.0 g of Fe2O3 and 20.0 g Al, Which reactant is limiting? What mass of Fe can be produced? What mass of the excess reactant remains after the limiting reactant is consumed? Set up an amounts table for this problem.
2. Some underwater welding is done via the thermite reaction, in which rust (Fe2O3) reacts with aluminum to produce iron and aluminum oxide (Al2O3). In one such reaction, 258 g of aluminum and excess rust produced 464 g of iron. What was the percent yield of the reaction?
3. Iron can be produced by the thermite reaction according to the following equation: Fe2O3 (s) +2Al (s) produces 2 Fe (s) + Al2O3 (s) a) If 100.0 g of Fe2O3 reacts with 30.0 g of Al, which one will be used up first? b) How much iron (in g) could be produced? c) If the only result in 45.0 g what is the percent yield?
Question 21 5 pts Determine the percent yield of a reaction that produces 30.0 g of Fe in the laboratory when Fe2O3 react with 20.0 g excess Al according to the following reaction. The theoretical yield of the reaction is 45.0 g of Fe. Fe2O3(s) + 2 Al(s) A1203(s) + 2 Fe(s) 81.9390 66.79 57.30% 44,49 75.0
Given the equation, which may or may not be balanced: Fe2O3(s) + CO(g) → Fe(s) + CO2(g) How many grams of Fe could be produced from the complete reaction of 3.196 grams of Fe2O3 with excess CO? grams Fe What is the percent yield of the reaction if only 1.571 grams of Fe are recovered after the reaction has completed? %
Determine the
percent yield of a reaction that produces 28 65 g of Fe when 50.0
00 g of Fez0s react with excess Al according to the following
reaction Fe2O3(s)+2 Al(s) Al2O3(s)+2 Fe(s)
W-SUMMERZC xCourse Home urse html?courseld-14733194&OpenVellumHMAC 01b27od2b2d7819a51616320b79deb92 10001 CHIM 151 0W Summer 2018 SCC e Home xam 3 2 Hide em Constant Part A Determine the percent yield of a reaction that produces 28 65 g of Fe when 50 00 g of Fe0s react with excess Al...
Question 5 2 pts The thermite reaction, which Dr. Jew set off in class (!), is the reaction of iron(III) oxide with aluminum according to the balanced reaction: Fe2O3(s) + 2 Al(s) --> Al2O3(s) + 2 Fe(l) dH = -849 kJ What would be the value of dH if... (a) ... the reaction is reversed? (b) ... the coefficients are all doubled? (c) ... the reaction is reversed and all coefficients are halved? value of dH if the reaction is...
How much energy is evolved during the reaction of 48.7 g of Al, according to the reaction below? Assume that there is excess Fe2O3. Fe2O3(s) + 2 Al(s) → Al2O3(s) + 2 Fe(s), ΔH°rxn = -852 kJ
For the reaction 2 Al + 3 H,SO -3H, + A1, (SO), how many grams of sulfuric acid, H2SO4, are needed to react completely with 51.9 g of aluminum, Al? 100 mass: 1/100 0/100 Consider the reaction. heat 2 Al(s) + Fe,0,(3) ***, ALO3(s) + 2 Fe(1) If 17.7 kg Al reacts with an excess of Fe,Og, how many kilograms of A1, O, will be produced? mass of A1,03 produced:
Consider the balanced chemical reaction that phosphorus and iodine react to produce phosphorus triodide: 2 P(s) + 3 I2(g) → 2 PI3(g) If 131 g of I2(s) area reacted with excess P(s) to produce 0.306 mol of PI3(g), what is the percent yield of PI3(g)?