3. Iron can be produced by the thermite reaction according to the following equation:
Fe2O3 (s) +2Al (s) produces 2 Fe (s) + Al2O3 (s)
a) If 100.0 g of Fe2O3 reacts with 30.0 g of Al, which one will be used up first?
b) How much iron (in g) could be produced?
c) If the only result in 45.0 g what is the percent yield?
159.7 g Fe2O3 reacts with 54 g Al.
So 100.0 g Fe2O3 reacts with (54×100.0)÷159.7 g = 33.8 g Al.
54 g Al gives 2×55.85 g iron.
So 30.0 g Al gives (2×55.85×30.0)÷54 g = 62.1 g
3. Iron can be produced by the thermite reaction according to the following equation: Fe2O3 (s)...
In the thermite reaction, iron (III) oxide is reduced by aluminum to give molten iron, Fe2O3 (s) + 2 Al (s) --> 2 Fe (l) + Al2O3 (s) If you begin with 10.0 g of Fe2O3 and 20.0 g Al, Which reactant is limiting? What mass of Fe can be produced? What mass of the excess reactant remains after the limiting reactant is consumed? Set up an amounts table for this problem.
2. Some underwater welding is done via the thermite reaction, in which rust (Fe2O3) reacts with aluminum to produce iron and aluminum oxide (Al2O3). In one such reaction, 258 g of aluminum and excess rust produced 464 g of iron. What was the percent yield of the reaction?
Iron oxide reacts with aluminum in an exothermic reaction. Fe2O3(s) + 2Al(s) → 2Fe(s) + Al2O3(s) The reaction of 5.00g Fe2O3 with excess Al(s) evolves 26.6 kJ of energy in the form of heat. Calculate the enthalpy change per mole of Fe2O3 reacted.
15. Consider the following reaction. 2Al (s) + Fe2O3 (s) → Al2O3 (s) + 2Fe (s) In one experiment 30.5 grams iron is formed when 104 g of Al is reacted with 90 g of Fe2Os. What is the percent yield? a. 100% b. 75% C. 50% d. 33% e. 25%
Consider the following balanced chemical reaction Fe2O3(s) + 2Al(s) → 2Fe(s) + Al2O3(s) What mass of iron can be produced if 50.0 g of Fe2O3 is mixed with 40.0 grams of Al?
19) The thermite reaction given below is one of the most exothermic chemical reactions known. It is involved in a variety of industrial processes including welding. Iron (111) oxide is reduced at such a high temperature that the iron formed is in the liquid phase (MP = 1538*C). How much energy is evolved during the formation of 100.0g of Fe (55.85 g/mole)? Fe2O3(s) + 2Al(s) → Al2O3(s) +2Fe11 H rxn -852 kJ
Question 21 5 pts Determine the percent yield of a reaction that produces 30.0 g of Fe in the laboratory when Fe2O3 react with 20.0 g excess Al according to the following reaction. The theoretical yield of the reaction is 45.0 g of Fe. Fe2O3(s) + 2 Al(s) A1203(s) + 2 Fe(s) 81.9390 66.79 57.30% 44,49 75.0
Aluminum oxide (Al2O3) is produced according to the following equation. 4 Al(s) + 3 O2(g) → 2 Al2O3(s) If the reaction occurs with an 82.4% yield, what mass of aluminum should be reacted with excess oxygen to produce 45.0 grams of Al2O3? a. 54.6 g Al b. 37.9 g Al c. 35.1 g Al d. 23.8 g Al e. 28.9 g Al How do we solve this problem
The highly exothermic thermite reaction, in which aluminum reduces iron (III) oxide to elemental iron, has been used by railroad repair crews to weld rails together. 2Al(s) + Fe2O3(s) 2Fe(s) + Al2O3(s) AH = -850 kJ What mass of iron is formed when 725 kJ of heat are released?
The thermite reaction, used for welding iron, is the reaction of Fe3O4 with Al. 8 Al (s) + 3 Fe3O4 (s) \longrightarrow ⟶ 4 Al2O3 (s) + 9 Fe (s) Δ H° = -3350. kJ/mol rxn Because this large amount of heat cannot be rapidly dissipated to the surroundings, the reacting mass may reach temperatures near 3000. °C. How much heat (in kJ) is released by the reaction of 19.3 g of Al with 63.2 g of Fe3O4? Enter a...