Question

A square, 34.0-turn coil that is 11.0 cm on a side with a resistance of 0.660n is placed between the poles of a large electromagnet. The electromagnet produces a constant, uniform magnetic field of 0.450 T directed out of the screen. As suggested by the figure, the field drops sharply to zero at the edges of the magnet. The coil moves to the right at a constant velocity of 1.80 cm/s. What is the current ij through the wire coil before the coil reaches the right edge of the field? Define counterclockwise current as positive and clockwise current as negative. N-turn coil What is the current i2 through the wire coil while the coil is leaving the field? B out of the screen A What is the current i3 through the wire coil after the coil leaves the field? A What is the total charge magnitude AQ that flows past a given point in the coil as it leaves the field? AQ=

Answer 1

a)

as the flux through the loop remain constant, so no current induced

i = 0 A

b)

current = induced emf / Resistance

. i = BL N v / R = 0.45 * 0.11* 34* 0.018 / 0.66

i = 0.0459 A

c)

same as (a)

d)

q = i t = i (L/v) = 0.0459* 0.11 / 0.018 = 0.2805 C

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