Question

7. A 6.2 ft tall mage in the mirror appears to be only 6.6in tall. a. Is the shopper's image upright or inverted? b. What is the mirrors radius of curvature? store is 17ft from a convex security mirror. The shopper notices that his ou place an object in front of a concave mirror with focal length f so that the image is upright Express your answer as a multiple of the focal length,f and thrice the size of the object? A dentist's mirror is 2 cm from a tooth. The image is located 6cm behind the mirror a. What kind of mirror is being used? b. What is the focal length of the mirror? c. What is the magnification of the mirror? d. is the image upright or inverted? 0. When you hold a spherical concave mirror with a 48.2-cm radius of curvature 19.4 cm in front of your f you see an image of your face in the mirror. Where is this image located, with respect to the mirror? -2 image with a magnification of 1.75 when the mirror is 1.0cm from a tooth.(Treat this problem as thog object and image lie along a straight line.) 21. A dentist uses a curved mirror to view teeth on the upper side of the mouth. Suppose she wants an up a. What kind of mirror is needed? h. What must be the radius of curvature of this mirror?

Answer 1

19.

(a)

A concave mirror

(b)

$\frac {1}{f}=\frac {1}{v}+\frac {1}{u}=\frac {1}{6}+\frac {1}{(-2)}$

$f=-3\: cm$

(c)

$m=\frac {-v}{u}=\frac {-6}{-2}=3$

$m=3$

(d)

The image is upright.

21.

(a)

A concave mirror

(b)

$\frac {1}{f}=\frac {1}{v}+\frac {1}{u}$

$m=-\frac {v}{u}=1.75$

$m=-\frac {v}{-1}=1.75$

$v=1.75\: cm$ (behind the mirror)

$\frac {1}{f}=\frac {1}{1.75}+\frac {1}{(-1)}$

$f=-2.33\: cm$

$R=2|f|=4.66\: cm$