Question

(a) If the fourth-order maximum for pure-wavelength light falling on a double slit is at an angle of 20.4°, at what angle (in degrees) is the fifth-order maximum? (b) What is the angle (in degrees) of the third minimum? (c) What is the highest-order maximum possible here?

Answer 1

Then

theta 1 = 20.4°

solution given data; 0, = 20.4° parta) dsino=ma dsino, = 4N - dsinaa=SA - . and, ® dsina, = 4 dsino - YA sa Sindi sino Sinoz non, sinda = 5 sind, Here 0,- 20.40 Boy sin0z = $ xsin 20.4 sin 02 = 0.4357 02 = sin '(0.4357) 102 = 25083" ] Ang

bpaget) dsinon = (2n+1) dsinona (an dsinon = (363)+1) so, sinon- / 1 put values, sinon = 7x Sinzo.4 So, sin2o.4 = 0.08714 On = sin" (2x0.06714) On = 17.769) AS c Rast) Ozgo then, asino = ma - so, med R 0.08714 ma 11047 allos I hope help you!!