Number of moles = Mass in gram / Molar mass
Number of moles of KHP = 1.523 g / 204.22 g/mol = 0.00746 mol
From reaction, 1.0 mol of KHP requires 1.0 mol of NaOH to reach the end point then 0.00746 mol of KHP will required 0.00746 mol of NaOH.
Volume of NaOH solution required = 15.30 ml = 15.30 L / 1000 = 0.0153 L
Molarity = number of moles of solute / Volume of solution in Litre
Molarity of NaOH = 0.00746 mol / 0.0153 L = 0.4876 mol/L = 0.4876 M
Problem: A 1.523 gram sample of KHP (molar mass=204.22 g/mol) was dissolved in 20.00 mL of...
A 1.413-g sample of KHP takes 19.43 mL of a NaOH solution to titrate it to a phenolphthalein end point. What is the molarity of the NaOH solution? The molar mass of KHP is 204.2g/mol.
A 40.0 mL solution containing 0.500 g of KHP was titrated with NaOH solution of unknown concentration, and the pH of the solution was measured after each known amount of NaOH was added. (KHP=potassium hydrogen phthalate; formula=KHC8H4O4; molar mass=204.22 g/mol). The acid base reaction occurs according to the following net ionic equation: HC8H4O4- (aq) + OH- (aq) ®C8H4O42- (aq) + H2O What is the molar concentration of KHP in the solution? If the titration required 24.0 mL of NaOH to...
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average molar mass?
CALCULATIONS A. NaOH Preparation: Approximate molarity of NaOH 0.48 M B. NaOH Standardization: Trial # Mass of KHP E 1.7249 1.9569 1.8799 Volume of NaOH 18.58 L 20.58mLihat 19.71 mL Molarity of NaOH 0.4544 M 0.4654M 0. 3 M 0.4668M Average molarity of NaOH: 0.4668 M 0.4622 M C. Molar Mass of NH X Salt 1. Volume of NaOH 0.025 0.025 0.025L 2. Molarity...
The titration of 0.9541g of KHP (molar mass=204.227 g/mol)requires 42.18 mL of NaOH solution. What is the concentration of the NaOH solution?
Find the percent mass of a 0.6708g sample of an unknown concentration of KHP (204.23g/mol) dissolved in 50ml of distilled water. Titrated with 27.04ml NaOH with a concentration of 0.0805M NaOH.
In an experiment, you dissolve 0.30 g of KHP (MM = 204.22 g/mol) in 20 mL of DI water and titrate the sample with 0.10 M NaOH. Calculate the volume (to the nearest mL) of NaOH required to reach the equivalence point. a) 3 ml b) 15 ml c) 20 ml d) 30 ml e) 100 ml
The titration of 0.9659 g of KHP (molar mass = 204.227 g/mol) requires 49.35 mL of NaOH solution What is the concentration of the NaOH solution? concentration: apling Learning, Inc. about us Careers privacy policy terms of use contact us help
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 ml water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the exact number of moles of KHP that will react with...
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 ml water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the exact number of moles of KHP that will react with...
Question 1 (2 points) How many moles of KHP are contained in a sample of 4.656 g KHP (Molar Mass = 204.22 g/mol)? 0.0228 moles KHP 0.0656 moles KHP 4656 moles KHP 0.0114 moles HD Question 2 (2 points) If the reaction between KHP and NaOH is: C8H.KOH + NaOH - H2O + CHAKO Na (KHP) How many moles of NaOH are needed to react with 4.656 g of KHP?! 0.0656 moles NaOH 0.0228 moles NaOH 0.0114 moles NaOH 4.656...