Question

For the following reaction, 12.9 grams of chlorine gas are allowed to react with 57.6 grams of sodium iodide. chlorine(g) + sodium iodide(s) — sodium chloride(s) + iodine(s) What is the maximum amount of sodium chloride that can be formed? 11.22 grams What is the FORMULA for the limiting reagent? | Nai | What amount of the excess reagent remains after the reaction is complete? 60.64 grams

something in my answers is wrong please I already got my first try wrong this is my last please get them right.

Answer 1

da gas mass = 12.99, de 9.0. 10. do Nal mass : 57.6 NeJ- mow - 149.89 cl2 tara 2 Nach tiz 2x58.44 + 253-8 g Mws Hagl 79.90 12.9 149-899 576 wti moles: 00906. molg: 0 -1819 8.23572. 0214214. - ela acts as limiting reagent because its having low moles compare with hal moles. " The maximum mass of Nac. is. To gogel To gogh a & Nad 2x58.44 12.99 a x 12.9x2x58.44 20.9. The maximum mass of sad is - 21.265g.

ch 12 hal 2 nacl thg ent: 12-9 12.9 4.W: 10.9 2x14989. moly: 129 70.9 da) 0.1819 6 3 109 89 oc- 545ug O anle mole of da 21. 26 notes of Nad formed by 12.9 g of che and 54.54g of May. so the excess ragent remaining after the reaction is = 57.6 - 54.54 = 13-06 - go any