Homework Answers
Answer
pH = 2.80
Explanation
Stepwise neutralisation reaction is
H2A + OH- ------> HA- + H2O pKa1 = 2.80
HA- + OH- ------> A2- + H2O pKa2 = 6.50
at one quarter neutralization , diprotic acid presents are H2A , HA-
[H2A]= [HA-]
Henderson - Hasselbalch equation is
pH = pKa + log([A-]/[HA])
pH = 2.80 + log(1)
pH = 2.80
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