Answer
pH = 2.80
Explanation
Dissociation of diprotic acid is as follows
H2A <------> HA- + H+ pKa1 = 2.80
HA- <-------> A2- + H+ pKa2 = 6.50
at half neutralization
H2A = HA-
Henderson - Hasselbalch equation is
pH = pKa + log([HA-]/[H2A])
pH = 2.80 + log1
pH = 2.80
Therefore
at quarter neutralization point , pH = 2.80
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