Question

What is the equation for the reaction between aqueous chloroacetic acid (ClCH2COOH) and aqueous NaOH? Correct...

What is the equation for the reaction between aqueous chloroacetic acid (ClCH2COOH) and aqueous NaOH? Correct me if wrong:

ClCH2COOH (aq) + NaOH (aq) ↔ ClCH2COO- (aq) + H2O (l) ??

or would the sodium ion combine with the conjugate base?

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Answer #1


the balanced equation is as follows

ClCH2COOH (aq) + NaOH (aq) ------------------> ClCH2COONa (aq) + H2O(l)

here the NaOH acts as base and it removes the proton in the -COOH group and then forms the acetate ion and in the equation you have to mention the Na+ in the product side along with conjugate base

here the ClCH2COOH ( acid ) and reacts with NaOH (base) forms the salt ClCH2COONa and the water H2O and it is neutralization reaction

answer => ClCH2COOH (aq) + NaOH (aq) ------------------> ClCH2COONa (aq) + H2O(l)

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