C(s) + H2O(g)
CO(g) + H2(g). K= 2.52
Let partial pressure of CO(g) = partial pressure of H2 = x atm and partial pressure of H2O(g) = 1-x at equilibrium .
K = 2.52 = x*x/(1-x)
x2 + 2.42x - 2.52 = 0
x = 0.7667 atm
Partial pressure of CO = partial pressure of H2 = 0.7667 atm
Partial pressure of H2O(g) = 1 - 0.7667 = 0.2333 atm
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> How is (1-x)(2.52)= 2.52-2.42x?
Fernan Matthew Enimedez Sun, Dec 19, 2021 10:11 PM