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- PCI) D ) 10. In cop 0.10-MN 4PCI() AH -1280k 4.ใณใน Assum - 4PCI(s) AH = -1774 kJ calculate 4.184 / & Cakeware for PCHD + C
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Answer #1

Q6:

P4 + 6 Cl2\rightarrow 4 PCl3. ∆H = -1280kJ/mol. ------(1)

P4 + 10 Cl2\rightarrow 4 PCl5. ∆H = -1774kJ/mol --------(2)

(Equation 2 - equation 1 )/4

PCl3 + Cl2\rightarrow PCl5.

∆H = (-1774-(-1280))/4 = -123.5kJ/mol (Answer)

Q7:

Heat absorbed = m.s.∆T = 155g×4.184J/g.℃ × (47.5-18.0)℃  

= 19131.34 J

= 19.13 kJ. (Answer)

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