A 100.0 mL100.0 mL solution containing 0.927 g0.927 g of maleic acid (MW=116.072 g/mol)(MW=116.072 g/mol) is...
A 100.0 mL100.0 mL solution containing 0.927 g0.927 g of maleic acid (MW=116.072 g/mol)(MW=116.072 g/mol) is titrated with 0.275 M KOH.0.275 M KOH. Calculate the pH of the solution after the addition of 58.0 mL58.0 mL of the KOHKOH solution. Maleic acid has p?apKa values of 1.92 and 6.27.
pH=
At this pH, calculate the concentration of each form of maleic acid in the solution at equilibrium. The three forms of maleic acid are abbreviated as H2M,H2M, HM−,HM−, and M2−,M2−, which represent the fully protonated, intermediate, and fully deprotonated forms, respectively.
[M2−]=
[HM−]=
[H2M]=
Homework Answers
![srail = 0.2175M, 58me = 0.2175x58 - 15.95 mondes {kat] = 0.275M, 58me. = 116.072 [H₂H] = loome, 0.927g +0.927 moles - 0.008 m](http://img.homeworklib.com/questions/e82001c0-7283-11ea-8b76-5dd2f27c91ea.png?x-oss-process=image/resize,w_560)
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A 100.0 mL100.0 mL solution containing 0.927 g0.927 g of maleic
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