Q#5. Calculate the pH of 0.15M C,HNH,1 (Strong electrolyte) solution. (K = for CH-NH, = 5.6...

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science chemistry

Answer 1

Answer #1

Ans 6: [H-] = KXc = V0.88 x 4 x 10-4 = 0.0187 pH=-log (H+) = -log(0.0187) = 1.73 % ionisation = KC x 100 = V4 x 10-4/0.88 x 1

Ans 8: pOH = -log [OH-] = -log(1 x 10-1) = 7 As we know pH + pOH = Kw = 14 Therefore, pH = 14 - POH = 14 - 7 = 7 or 1 x 10-7

Answer 2

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