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7. A block of mass m = 5.00 kg slides down a surface inclined 36.9° to the horizontal as shown below. The coefficient of kine

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MK = 0.20 Given, m = 5kg, 0 = 36.9° I = 0.30kg m2 Free body diagram: ad AFN mgsino mguso on {avate forces: f = 4 FN = all mymgsino - umgos o -ma - I a R2 ale + m] = mg (sino - e cuso) mg (sino - u ws 0 ) a 5kg x 9.81 m/ 2 [sin (36.9) - 0-2 Cos (36-9

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