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A hollow ball with radius R- 2 cm has a charge of -2 nC spread uniformly over its surface (see the figure). The center of the ball is at Pt --3, o, 0> cm. A point charge of 5 nC is located at Ps-<3, 0, 0> cm. (The diagram below is not drawn exactly to scale) Р, Х P3 . What is the net electric field at location P2-0,5, 0 cm? x N/C At a particular instant an electron is at location P2. What is the net electric force on the electron at that instant? N.

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The electric field at P; due to the charge at is, kqi (5 kq, The electric field at P due to the charge on hollow ball is, Cos@ I-X+COS (5i) The resultant electric field is, E=B+E, kq, COS (3x 10) 5x10-2 3x10)+(5x102) 5 x10 3x 105x10 = (1323 5.29)(-0.85749x+ 0.5144955)+(5294. 1176)(-0.85 749-0.514495y (98109)(5x10°) 3x102+(5x102 (9x10%)(2x10) (3x10-27-(5x10-3 3× 10-2 ).-5× 10-2 ). (3x10) 3x10+(5x 102) (3x10-2)2+/5x10 (3x10-2)2+(5x10-2 )2 --11.35x103x+6.8 1x10%y+(-4.54 x 10x-2.73x10%y - -15.89x10 x+4.08x10y The magnitude of the electric field is, E-V(15.89×103).(4.08 x 10%) The net force is, (1.6x10-19)(1.67x104) = 2.67×10-15 N

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