Question

At 234 degrees Celsius, the K eq for the reaction is 4.93x 1 ^1 1A+5B leftrightarrow 4AB. What is kp?

At 234 °C, the Key for the reaction is 4.93 · 101: -1 A+5B H 4 AB What is Kp? Show your work:

Answer 1

Answer:

1. K_{​​​​​​P} = 2.77 × 10^-6

2. K_{​​​​​​eq} = 8.76 × 10⁸

Explanation:

To solve these questions we need the following formula,

K_{​​​​​​P} = K_{​​​​​eq} (RT)^$\Delta$n

Where,

R = universal gas constant

T = temperature

$\Delta$n = (number of moles of products - number of moles of reactants)

1.

1 A +5B 4 AB No. of moles of product = 4 No. of moles of reactant - 1+5=6 So, An= 4-6=-2 Keq = 4.93×10² T= 234°C = 507.15 K R= 8. 314 J.Kt. mal Put these values in the equation fore Kp. Kp = 4.93x 10² (8.314 x 507.15) 2 [Kp = 2.778 109

2.

For the second question, we will use the same equation.

$1 A +5B\leftrightarrow 4AB$

Here,

An = -2 Kp = 4.938 10² = 507.15K R = 8.314 J.K". mal" put these values in the equation for Kp 4.934 18 ² = keq (8.3144 507.152 Keg = 4.93% 10² (8.314x507.152 Keg = 876475577.6 Keq = 8.76X 1087