![18.0 6.18 The following data were obtained on the initial rate of isomerization of a compound S catalyzed by an enzyme E: [S]](http://img.homeworklib.com/questions/2d05bdc0-7300-11ea-a8e9-c38e04515dc3.png?x-oss-process=image/resize,w_560)
Homework Answers
| [S]0 | [E]0 | Initial Rate (R) | S2/S1 | R2/R1 | log(S2/S1) | log(S2/S1) | Order [S] | Order [E] | Final Order of reaction |
| 1 | 1 | 4.5 | 2 | 2 | 0.30103 | 0.30103 | 1.00 | 1.08368511 | 2 |
| 2 | 1 | 9 | 1.5 | 1.66666667 | 0.17609126 | 0.22184875 | 1.26 | 0.92994704 | 2 |
| 3 | 1 | 15 | 1.33333333 | 1.2 | 0.12493874 | 0.07918125 | 0.63 | 1 | 2 |
| 4 | 1 | 18 | 0.25 | 0.82222222 | -0.60206 | -0.0850108 | 1.09134066 | ||
| 1 | 3 | 14.8 | 2 | 1.68918919 | 0.30103 | 0.22767829 | 0.76 | 1.14721355 | 2 |
| 2 | 3 | 25 | 1.5 | 1.8 | 0.17609126 | 0.25527251 | 1.45 | 1.30286657 | 3 |
| 3 | 3 | 45 | 1.33333333 | 1.32666667 | 0.12493874 | 0.12276182 | 0.98 | 1.15143328 | 2 |
| 4 | 3 | 59.7 | 0.25 | 0.98659966 | -0.60206 | -0.005859 | 1.14864609 | ||
| 1 | 10 | 58.9 | 2 | 2.03735144 | 0.30103 | 0.30906595 | 1.03 | ||
| 2 | 10 | 120 | 1.5 | 1.5 | 0.17609126 | 0.17609126 | 1.00 | ||
| 3 | 10 | 180 | 1.33333333 | 1.32222222 | 0.12493874 | 0.12130445 | 0.97 | ||
| 4 | 10 | 238 | |||||||
From the above table of calculations, it is clear that the overall order of the reaction is 2
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18.0 6.18 The following data were obtained on the initial rate of isomerization...
Please show your work, Thanks! 6.18 The following data were obtained on the initial rate of isomerization of a c...
Please show your work, Thanks!
6.18 The following data were obtained on the initial rate of isomerization of a compound S catalyzed by an enzyme E: S]./(mmol dm") Va/(mmol dms) 2.00 3.00 1.00 4.00 15.0 9.0 4.5 (a) (b) 18.0 45.0 25.0 14.8 59.7 180.0 120.0 238.0 (c) 58.9 The enzyme concentrations are (a) 1.00 mmol dm, (b) 3.00 mol dm, and (c) 10.0 mmol dm Find the orders of reactions with respect to S and E, and the rate...
The following intial rate data were obtained by adding 2.5 μg of a purified enzyme having...
The following intial rate data were obtained by adding 2.5 μg of a purified enzyme having molecular weight of 42,300 Daltons into 100 mL of water with the indicated concentrations of substrate C) So (mmol/L) 1.00 2.00 4.00 8.00 (HmoVLs) 4.50 7.90 11.10 15.20 Calculate the value of kCAT. KM and the pseudo first order rate constant.
The key factor that controls the initial rate of an enzyme catalysed reaction (Vo) is the...
The key factor that controls the initial rate of an enzyme catalysed reaction (Vo) is the concentration of the substrate of the reaction ([S]). In Damon's Michaelis-Menten experiment, the highest concentration of substrate used was 500 UM. What do you think will happen to the reaction velocity if higher concentrations of substrate were used? Select one: a. Vo will reach a plateau at higher (S) values O b. Vo will increase exponentially as (S) is increased O c. Vo will...
Problem #3 (20 marks) The following kinetic data (initial rates) were obtained for the reaction 2...
Problem #3 (20 marks) The following kinetic data (initial rates) were obtained for the reaction 2 ICI(g) + H2(g) → 12(g) + 2 HCI (9) Experiment [Cl]. (mmol/L) [Hz]. (mmol/L) V. (mol/L s) 3.0 3.0 14.8 X10-7 3.0 1.8 8.9 x10-7 1.5 1.8 4.44 x 10-7 3.7 1.3 ? (a) Write the rate law for the reaction (b) From the data, determine the value of the rate constant (c) Use the data to predict the reaction rate for experiment 4.
Products yielded the following data: 6. A reaction A+B+C Initial concentration (mmol L-1) Initial rate (-d[Al/dt) (m...
Products yielded the following data: 6. A reaction A+B+C Initial concentration (mmol L-1) Initial rate (-d[Al/dt) (mmol L-1 s-1) Experiment AI) 0 [C]O Initial rate (-dA/dt mM I-S-1) [BJO 8.72 11.25 1.25 1.25 2.50 1.25 1.25 17.4 3 1.25 3.02 1,25 50.84 3.75 457 1.25 3.02 a) Write the rate law for this reaction b) If the initial reactant concentrations were [A]0 2 mmol L-1, [Bl0 1.5 mmol L-1 and [C]0 =1.15 mmol L-1, indicate what would be the initial...
3) Enzyme kinetics are determined under initial rate conditions, wherein the initial substrate concentrations changes very...
3) Enzyme kinetics are determined under initial rate conditions, wherein the initial substrate concentrations changes very little, because: (A) Products do not accumulate and inhibit the forward reaction (B) Enzymes are unstable under most assay conditions, and rapidly lose activity (C) The substrate concentration does not change appreciably and so does not create an additional variable (D) All of the above (E) Some of the above
Please show the working The following data were obtained for the decomposition of N20s in CCl4....
Please show the working
The following data were obtained for the decomposition of N20s in CCl4. The following data were collected. 2. 0423 753 1116 1582 1986 2343 0.35 Time/ s dN2Os/ mol dm 1.46 1.09 0.89 0.720.54 Calculate: (a) Average rate of reaction. (b) Initial instantaneous rate. (c) [N20s] at 3.5 x103 s after the start of the reaction. (d) Order with respect to N205 (e) Rate law for this reaction: 0.43
1. M. L. Bender and T. H. Marshall [J. Am. Chem. Soc., 90, 201(1968)] studied the elastase-mediated hydrolysis of p-nit...
1. M. L. Bender and T. H. Marshall [J. Am. Chem. Soc., 90, 201(1968)] studied the elastase-mediated hydrolysis of p-nitrophenyl trimethylacetate to produce p-nitrophenol. These authors have proposed the following mechanism for this reaction: k. k2 E A ES where S, the substrate, is p-nitrophenyl trimethylacetate; P, the product, is p-nitrophenol; and A is trimethylacetiç acid. k,= 150 m3mole-ksec and k2= 2.60 ksec1. (a) Derive an equation for the rate of production of species P in terms of ki, k2,...
The following data has been obtained for an enzyme-catalyzed reaction with two different initial enzyme concentrations...
The following data has been obtained for an enzyme-catalyzed reaction with two different initial enzyme concentrations of 0.025g/L and 0.015g/L. V (g/L.min) [S] (g/L) Eo = 0.025g/L Ep = 0.015g/L 56.8 1.75 1.05 28.4 1.58 0.97 19.1 1.47 0.89 14.3 1.38 0.83 11.4 1.31 0.77 9.4 1.22 0.73 8.2 1.15 0.69 7.1 1.08 0.66 (a) Using the Lineweaver-Burke plot, determine Km and Vm for Eo = 0.025g/L (b) Using the Lineweaver-Burke plot, determine Km and Vm for Ep = 0.015g/L...
1-The rate constant of a chemical reaction was measured at several temperature values and a plot...
1-The rate constant of a chemical reaction was measured at several temperature values and a plot of ln k (on the y-axis) was plotted against 1/T (on the x-axis, temperature was measured in Kelvin). If the slope of the plot was -9.21 x 103 K and the y-intercept was 13.0, what is the activation energy (EA) of the reaction in kJ mol-1? 2-In an enzyme-catalyzed reaction, the rate of the reaction depends on which of the following at very low...
Please show your work, Thanks!
6.18 The following data were obtained on the initial rate of isomerization of a compound S catalyzed by an enzyme E: S]./(mmol dm") Va/(mmol dms) 2.00 3.00 1.00 4.00 15.0 9.0 4.5 (a) (b) 18.0 45.0 25.0 14.8 59.7 180.0 120.0 238.0 (c) 58.9 The enzyme concentrations are (a) 1.00 mmol dm, (b) 3.00 mol dm, and (c) 10.0 mmol dm Find the orders of reactions with respect to S and E, and the rate...
The following intial rate data were obtained by adding 2.5 μg of a purified enzyme having molecular weight of 42,300 Daltons into 100 mL of water with the indicated concentrations of substrate C) So (mmol/L) 1.00 2.00 4.00 8.00 (HmoVLs) 4.50 7.90 11.10 15.20 Calculate the value of kCAT. KM and the pseudo first order rate constant.
The key factor that controls the initial rate of an enzyme catalysed reaction (Vo) is the concentration of the substrate of the reaction ([S]). In Damon's Michaelis-Menten experiment, the highest concentration of substrate used was 500 UM. What do you think will happen to the reaction velocity if higher concentrations of substrate were used? Select one: a. Vo will reach a plateau at higher (S) values O b. Vo will increase exponentially as (S) is increased O c. Vo will...
Problem #3 (20 marks) The following kinetic data (initial rates) were obtained for the reaction 2 ICI(g) + H2(g) → 12(g) + 2 HCI (9) Experiment [Cl]. (mmol/L) [Hz]. (mmol/L) V. (mol/L s) 3.0 3.0 14.8 X10-7 3.0 1.8 8.9 x10-7 1.5 1.8 4.44 x 10-7 3.7 1.3 ? (a) Write the rate law for the reaction (b) From the data, determine the value of the rate constant (c) Use the data to predict the reaction rate for experiment 4.
Products yielded the following data: 6. A reaction A+B+C Initial concentration (mmol L-1) Initial rate (-d[Al/dt) (mmol L-1 s-1) Experiment AI) 0 [C]O Initial rate (-dA/dt mM I-S-1) [BJO 8.72 11.25 1.25 1.25 2.50 1.25 1.25 17.4 3 1.25 3.02 1,25 50.84 3.75 457 1.25 3.02 a) Write the rate law for this reaction b) If the initial reactant concentrations were [A]0 2 mmol L-1, [Bl0 1.5 mmol L-1 and [C]0 =1.15 mmol L-1, indicate what would be the initial...
Please show the working
The following data were obtained for the decomposition of N20s in CCl4. The following data were collected. 2. 0423 753 1116 1582 1986 2343 0.35 Time/ s dN2Os/ mol dm 1.46 1.09 0.89 0.720.54 Calculate: (a) Average rate of reaction. (b) Initial instantaneous rate. (c) [N20s] at 3.5 x103 s after the start of the reaction. (d) Order with respect to N205 (e) Rate law for this reaction: 0.43
1. M. L. Bender and T. H. Marshall [J. Am. Chem. Soc., 90, 201(1968)] studied the elastase-mediated hydrolysis of p-nitrophenyl trimethylacetate to produce p-nitrophenol. These authors have proposed the following mechanism for this reaction: k. k2 E A ES where S, the substrate, is p-nitrophenyl trimethylacetate; P, the product, is p-nitrophenol; and A is trimethylacetiç acid. k,= 150 m3mole-ksec and k2= 2.60 ksec1. (a) Derive an equation for the rate of production of species P in terms of ki, k2,...
The following data has been obtained for an enzyme-catalyzed reaction with two different initial enzyme concentrations of 0.025g/L and 0.015g/L. V (g/L.min) [S] (g/L) Eo = 0.025g/L Ep = 0.015g/L 56.8 1.75 1.05 28.4 1.58 0.97 19.1 1.47 0.89 14.3 1.38 0.83 11.4 1.31 0.77 9.4 1.22 0.73 8.2 1.15 0.69 7.1 1.08 0.66 (a) Using the Lineweaver-Burke plot, determine Km and Vm for Eo = 0.025g/L (b) Using the Lineweaver-Burke plot, determine Km and Vm for Ep = 0.015g/L...
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