Question

The key factor that controls the initial rate of an enzyme catalysed reaction (Vo) is the concentration of the substrate of the reaction ([S]). In Damon's Michaelis-Menten experiment, the highest concentration of substrate used was 500 UM. What do you think will happen to the reaction velocity if higher concentrations of substrate were used? Select one: a. Vo will reach a plateau at higher (S) values O b. Vo will increase exponentially as (S) is increased O c. Vo will decrease at higher [S] values. d. Vo will increase continually in proportion to [S] O

Answer 1

Ang- [Mechalies - Menten Rabahonap) Vo=Vmax. [s] moin) mini Km + [5] while, voy rate of reaction Vmax.y max. rate of sxn. [s] > cheme substante concentration km y michalie-menten constant s Plateau (at high) [s] 1 (Vo) Umset (mm linear (at low [s]) Kmart 2 km [s] (mm) -7 y at a very [s] value very [s] walue (ie- [s] >> km) .. equation © will be Vom Vmax. [8] = Vmax. Thence it value ie plateau) reaches to constant a

0 ii cu higher concentration of substrate- option @ + vo will reach a plateau. 3. (2 Unit of Vmax. = 1mm-mint option (a since it is the velocity at highest substrate concentration hence it will have some content unit as velocity at low (s) valve, ie. (rs] << km) :: Vos Umax. [5] = con 84 x (s] =>{vo = Const- [5] [s] Helinear y Activity of enzyme depends how well it bindi with substrate which is called it's a effinity. higher im value decreases o velocity of xn from equation ③ O., hence it is inversle proportional to affinity. y option , 4 d are correct. hence option ® is incorrect. km