what is the increase in potential energy when a 200 N block of ice is lifted...

Question

Question

what is the increase in potential energy when a 200 N block of ice is lifted a vertical distance of 2.5 m?

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Answer 1

Answer #1

Increase in potential energy is given by:

dPE = W*dh

W = Weight of block = 200 N

dh = change in height = 2.5 m

So,

dPE = 200 N*2.5 m

dPE = increase in potential energy = 500 J

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Answer 2

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