work done by applied force
W = 50 * 0.5 * cos 180
W = -25 J
we know
change in kinetic energy = work done by applied force + work done by gravity
80 = - 25 + mgdcos ( 90 - 50)
80 + 25 = m * 9.8 * 0.5 * cos 40
m = 27.973 Kg
The figure below shows a block of ice sliding down a frictionless ramp at an angle...
Chapter 07, Problem 019 [1] Your answer is partially correct. Try again. In the figure here, a block of ce slides down a frictionless ramp at angle ?:50.0 while an ice worker pulls on the block wa a rope with a orce that as a magnitude of 50.0 N and is directed up the ramp. As the block slides down through distance d = 0.450 m along the ramp, its kinetic energy increases by 82.0 J. How much greater would...
7. A block of ice of mass m = 12 kg slides dom a frictionlons ramp at an angle 8 = 50° while an ice worker pulls on the block (via a rope) with & constant force that has a magnitude F 50N and is directed up the ramp. While this is happening the block slides down the incline through & distanced=0.50 m. Givens: m = 12 kg, F, -50N, d =0.50m, 8 = 50 g 9.8m/s? (a) Draw a...
A small block with mass 0.221 kg is sliding down a frictionless ramp that is inclined at an angle of 53.1
a) what was the acceleration of the block down the ramp before
the rope is pulled?
b) what was the acceleration of the block down the ramp after
the rope is pulled?
A4 kg block is released from rest at the top of a frictionless plane of length 9m that is inclined at an angle of 21 degrees to the horizontal Acord is attached to the block and trails along behind it. When the block reaches a point 3 m...
A block slides down a frictionless ramp, which makes a 30 degree angle to the horizontal floor. The block slides the full 180m all the way down the ramp, where it encounters a flat surface with friction. It slides for 250m before it finally comes to rest. a.) what is the speed at the bottom of the ramp? b.) What is the coefficient of friction on the flat surface? c.) What is the total time the block was in in...
A block is placed on a frictionless ramp at a height of 1.35m above the ground. Starting from rest, the block slides down the ramp. At the bottom of the ramp, the box slides onto a frictionless horizontal track without slowing down. What is the speed of the block on the horizontal track?the angle of the track is 44.3 degrees
1. (P) The figure below shows an 18.0kg crate of salami sliding down a ramp on a (massless) rope that is wrapped around a disk of radius 0.25m and mass 6.0kg. The coefficient of kinetic friction between the crate and ramp is μ k-0.24. What is the magnitude of the disk's angular acceleration? 30° A 3.1 rad/s2 B 6.7 rad/s2 C 9.8 rad/s2 D 11.4 rad/s2 E 13.7 rad/s2
1. (P) The figure below shows an 18.0kg crate of salami sliding down a ramp on a (massless) rope that is wrapped around a disk of radius 0.25m and mass 6.0kg. The coefficient of kinetic friction between the crate and ramp is μ k-0.24. What is the magnitude of the disk's angular acceleration? 30° A 3.1 rad/s2 B 6.7 rad/s2 C 9.8 rad/s2 D 11.4 rad/s2 E 13.7 rad/s2
A block (6 kg) starts from rest and slides down a frictionless ramp #1 of height 6 m. The block then slides a horizontal distance of 1 m on a rough surface with kinetic coefficient of friction μk = 0.5. Next, it slides back up another frictionless ramp #2. Find the following numerical energy values: 1.Initial gravitational potential energy on Ramp #1: U1G = J 2.Kinetic energy at bottom of Ramp #1 before traveling across the rough surface: K =...
3) Referring to the picture below, consider a block of mass m-1kg, sliding down a ramp with that is frictionless. The block continues to slide a distance d along the table, which has coefficient of friction u 0.2. Using conservation of energy answer the following: a If the block starts at a height h=5.1m how fast is it going at the very bottom of the ramp? b. The block comes to a stop a distance, d, from the bottom of...