A small block with mass 0.221 kg is sliding down a frictionless ramp that is inclined...

Question

Question

A small block with mass 0.221 kg is sliding down a frictionless ramp that is inclined at an angle of 53.1

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Answer 1

Answer #1

a) normal force = gmcos(theta) = 9.8*0.221*cos(53.1) = 1.3004 N

b) force = 9.8*0.221*sin(53.1) = 1.732 N

Answer 2

Answer #2

normal force = mg cos theta

= 0.221 * 9.80 * cos53.1

= 1.3 N

part b)

F g = mg sin theta

= 0.221 * 9.8 * sin (53.1)

= 1.73 N

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Answer 3

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