Question

3. If 9.00 grams of potassium carbonate was used in the reaction, how many grams of potassium bromide would be obtained? g potassium bromide

Answer 1

Ans 3 :

Mol potassium carbonate = mass / molar mass

= 9.00 g / 138.205 g/mol = 0.0651 mol

each mol potassium carbonate makes 2 mol potassium bromide

so mol of potassium bromide = 2 x 0.0651 mol = 0.130 mol

Mass of potassium bromide = mol x molar mass

= 0.130 mol x 119.002 g/mol

= 15.5 g