Question

1. How many grams of Pb2+ are present in 2.54 grams of lead(II) bromide? grams Pb2+ 2. How many grams of lead(II) bromide contain 1.26 grams of Pb2+? grams lead(II) bromide.

Answer 1

0 Pb Brz P6+2 + 2 Br- Now, moles of Pb Br2 = mass = = 2.54g molar mass. 367.01 glmol 56.99x10-3 mol Now, moles of P6+2 = moles of Pb Bry » mass of P6*2 = moles x molar mass = 6.92X10-3 mol x 207.glmol = (1.434 g) ☺ Moles of P6*2= mass = 7:26 - molar mass 207. 2 glmol = 6.08x10-3 mol Now, moles of Pb Br2 = moles of P6+2 & mass of Pb Br = moles x molar man • 6.08x10={mol x 367,01 g/mol