Question

(a) How many milliliters of a stock solution of 11.0 M HNO, would you have to use to prepare 500 mL of 0.200 M HNO,? ml (b) If you dilute 21.0 mL of the stock solution from part a) to a final volume of 3.00 L, what will be the concentration of the diluted solution? (Watch the 7. -13 points My (a) How many milliliters of a stock solution of 12.0 M HNO, would you have to use to prepare 0.500 L of 0.200 M HNO,? mi (b) If you dilute 30.0 mL of the stock solution from part a) to a final volume of 4.00 L, what will be the concentration of the diluted solution?

Answer 1

6.

a)

Moles of HNO₃

= M₁V₁ = M₂V₂

Or , M₁ × 11.0 = 0.200 × 500

Or, M₁ = 9.09 mL.

9.09 mL of stock solution is needed.

b)

Final volume (V₂) = 3.00 L = 3.00×1000 mL

Now,

M₁V₁ = M₂V₂

Or, 11.0× 21 = M₂ × (3.00 × 1000)

Or , M₂ = (11.0×21/3000) = 0.077 M.

Concentration of dilute solution = 0.077 M.

7

M₁V₁= M₂V₂

Or, 12 × V₁ = 0.200 × 0.500 L

Or, V₁ = (0.200×0.500/12)

Or, V₁ = 0.0083 L = 0.0083×1000 mL = 8.33 mL.

Volume of stock solution needed = 8.33 mL.

b)

Final volume (V₂) = 4.00×1000 = 4000 mL

Now,

M₁V₁= M₂V₂

Or, 12 × 30 = M₂ × (4.00 ×1000)

Or , M₂ = (12×30/4000) = 0.09 M.

Concentration of dilute solution = 0.09 M