Question

A. How many milliliters of a stock solution of 5.60 M HNO3 would you have to use to prepare 0.180 L of 0.530 M HNO3?

B. If you dilute 20.0 mL of the stock solution to a final volume of 0.350 L , what will be the concentration of the diluted solution?

Answer 1

1 ) According to Dilution law,

M _{​​​​1}​​​​​ V​​​​​​1 = M2 V2

Here. M1 = 5.60 M. M2 = 0.53 M

V1 = ? V2 = 0.180 Lit =( 0.180 x 1000) ml

5.60 M x V1 = 0.53 M x (0.180 x 1000) ml

V1 = 0.53 M x 180 ml / 5.60 M

V1 = 17.036 ml HNO3

2 ) Molarity of Stock solution ( M1) = 5.6 M

V1 = 20 ml

M2 = ?

V2 = 0.35 Lit =( 0.35 x 1000) ml

V2 = 350 ml

From Dilution law, M1 V1 = M2 V2

M2 = M1 V1 / V2

M2 = 5.6 M x 20 ml / 350 ml

M2 = 0.32 M HNO3