At an enzyme concentration of 1microM the Vmax is 100microM/min and the Km is 20nm. At...
At an enzyme concentration of 1microM the Vmax is 100microM/min and the Km is 20nm. At an enzyme concentration of 2microM, what would the V0 be at a substrate concentration of 40mM?
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![from that enzyme kinetics we know Vmax [E.] So, if at [eo] = 1 MM, Vmax = 100 MM/min then at [E] 22 MM , Donor = 200 MM /min](http://img.homeworklib.com/questions/893d6480-734a-11ea-bf44-b9522ecd2c63.png?x-oss-process=image/resize,w_560)
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At an enzyme concentration of 1microM the Vmax is
100microM/min and the Km is 20nm. At...
a. An enzyme has a Vmax of 100 umol/min and a Km of 40 uM. When...
a. An enzyme has a Vmax of 100 umol/min and a Km of 40 uM. When substrate concentration is 40 uM what is the initial reaction rate? b. An enzyme with a Vmax of 100 umol/minute and a Km of 10 uM was reacted with a irreversible active site specific inhibitor. After reaction with the inhibitor, the enzyme was assayed using a 2 mM concentration of substrate, and it gave a reaction rate of 20 umol/min. What percentage of the...
What is the rate of an enzyme catalyzed reaction if the Vmax is 100µmol S→P/min and...
What is the rate of an enzyme catalyzed reaction if the Vmax is 100µmol S→P/min and the Km is 7 mM and the substrate concentration is 11mM? Is the enzyme working at Vmax? What if the substrate concentration is raised to 25mM?
Consider the enzyme-catalyzed reaction with Vmax=164 (μmol/L)min−1 and KM=32μmol/L. Part A If the total enzyme concentration...
Consider the enzyme-catalyzed reaction with Vmax=164 (μmol/L)min−1 and KM=32μmol/L. Part A If the total enzyme concentration was 6 nmol/L, how many molecules of substrate can a molecule of enzyme process in each minute? Express your answer to three significant figures. kcat kcat = 2.73×104 min−1 Part B Calculate kcat/KM for the enzyme reaction.
An enzyme catalyzes a reaction with a Km of 9.00 mM and a Vmax of 3.95...
An enzyme catalyzes a reaction with a Km of 9.00 mM and a Vmax of 3.95 mM·s–1. Calculate the reaction velocity, v0, for the following substrate concentrations: A. 1 mM B. 9 mM C. 11 mM
An enzyme catalyzes a reaction with a Km of 7.00 mM and a Vmax of 4.00...
An enzyme catalyzes a reaction with a Km of 7.00 mM and a Vmax of 4.00 mM·s–1. Calculate the reaction velocity, v0, for the following substrate concentrations. A) 1.25 mM B) 7.00 mM C) 10.0 mM
An enzyme catalyzes the reaction A ⇌ B. The enzyme is present at a concentration of...
An enzyme catalyzes the reaction A ⇌ B. The enzyme is present at a concentration of 2 nM, and the Vmax is 1.2 μM s−1. The Km for substrate A is 10 μM. Calculate the initial velocity of the reaction, V0, when the substrate concentration is (a) 2 μM, (b) 10 μM, (c) 30 μM.
An enzyme has a Km of 64.9 mM, determine the fraction (ratio) of Vmax, I.e., v/Vmax,...
An enzyme has a Km of 64.9 mM, determine the fraction (ratio) of Vmax, I.e., v/Vmax, that would be obtained at each substrate concentration below. a. 3.25 mM b. 64.9 mM c. 694 mM d. 6.49 M e. 64.9 M
Which of the following statements is FALSE? Km is the [S] at which V0=Vmax V0 is...
Which of the following statements is FALSE? Km is the [S] at which V0=Vmax V0 is the closest to Vmax when [S] is less than Km As [S] increases, V0 gets closer to Vmax Vmax occurs when the enzyme is saturated with substrate
1. An enzyme has a km of 4.7 X 105M. If the Vmax of the preparation...
1. An enzyme has a km of 4.7 X 105M. If the Vmax of the preparation is 224M/min, what velocity would be observed in the presence of 2 X 10^M substrate and 5 X10+M a competitive inhibitor. Ki is 3 X 10^M. What is the degree of inhibition? (10pts)
5. The Km of an enzyme of an enzyme-catalyzed reaction is 6.5 uM. What substrate concentration...
5. The Km of an enzyme of an enzyme-catalyzed reaction is 6.5 uM. What substrate concentration will be required to obtain 55% of Vmax for this enzyme? (10 pts)
1. An enzyme has a km of 4.7 X 105M. If the Vmax of the preparation is 224M/min, what velocity would be observed in the presence of 2 X 10^M substrate and 5 X10+M a competitive inhibitor. Ki is 3 X 10^M. What is the degree of inhibition? (10pts)
5. The Km of an enzyme of an enzyme-catalyzed reaction is 6.5 uM. What substrate concentration will be required to obtain 55% of Vmax for this enzyme? (10 pts)
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