Question

Calculate the volume, in milliliters, for each of the following that provides the given amount of solute: a. 12.5 g of Na2CO, from a 0.120 M Na CO, solution b. 0.850 mol of NaNO, from a 0.500 M NaNO, solution c. 30.0 g of LiOH from a 2.70 M LiOH solution

Answer 1

1 0 .120 m No 03. motiof Nazco e 1000 ml son condam 0.12.ome Molor mood Na, coz 105.9888 gmert 0-120 me now, 0-120 ml x 105.98€88 mor 0120x105.98889 of ma, coz. ox 105.78888 of Na, coz is arofred in woom2 9 8 m, wg is mofreem 12-5x 1000 m2 0.120XL05.9888 982-8 ml 12.5g of My Ws is an 0.500 m NaNO₃ 3o.soomol Nano, s drndred m room2 0.850 mil warre, is dinolved in 0.85 0.500 = 1700mL 9 2.70 M LOW, le 1000 ml solri contorn q.70 ml of ra 4:04. Molors menot LOH = 23.95 g mot 2.70 mol of LiOH = 2.70 xhol x 23.95 gomoll of 404 = 2.70823-95 g of 404 2.70x23.25 g of the dinolved in 1000 ml 30 g of LiOH is andream 30x7000 ml 2.70x23.95 > 463.9 m2 NS, V22 B2LX6M = 61X2 24x6m. Osz = 26 de = zm Final concentration in zm

VS = V2 3 0.5LX 12 m = 3LX S₂ 0.52x72m BeF - Osh 3 = 2M imal concertation is am (c) vs - vele B 100ml x 25% (m/w) - 100m2 xq 3 = coml x 25% (m/) 3 B roome + S₂ = 2.54. (m/) frond concentration = 2.5% (m) (d) wisi =V22 B 50 m2 x 13% (m/v) = 200mlys BS = somal x157.com n = 2007 * $ = 3% (m/s) knal concentration = 3% (m/v)