Question

Question 36 of 50 Submit Using the equations N2(g) + 3 H2(g) - 2 NH; (g) AH = -91.8 kJ/mol C(s) + 2 H (g) – CH2 (g) AH° = -74

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Here you go:

Given Equations are:- N2Cg) +3 My (9) ► 2UwMz.rg2, 0405-91.8 Kg/mol C(s) + 24 (g) Chulg), DH =-7419 KJ/mol M299) + 2 Ces) +,

Thus, final reaction enthalpy is = +255.95 kj/mol

Add a comment
Know the answer?
Add Answer to:
Question 36 of 50 Submit Using the equations N2(g) + 3 H2(g) - 2 NH; (g)...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Using the equations N2 (g) + 3 H2 (g) → 2 NH3 (g) AH° = -91.8...

    Using the equations N2 (g) + 3 H2 (g) → 2 NH3 (g) AH° = -91.8 kJ/mol C(s) + 2 H2 (g) → CH4 (g) AH° = -74.9 kJ/ mol H2 (g) + 2 C(s) + N2 (g) → 2 HCN (g) AH° = 270.3 kJ/mol Determine the enthalpy for the reaction CH4 (g) + NH3 (g) → HCN (g) + 3 H2 (g).

  • Dok Solutions Chex G tb ofibular syndesmosis articuli X study guide lab practical-Goog x + Question...

    Dok Solutions Chex G tb ofibular syndesmosis articuli X study guide lab practical-Goog x + Question 3 of 20 Using the equations N2(g) + 3 H2(g) - 2 NH3 (9) AH = -91.8 kJ/mol C(s) + 2 H (g) – CHK (g) AH = -74.9 kJ/mol H (g) + 2 C(s) + N (g) + 2 HCN (g) AH = 270.3 kJ/mol Determine the enthalpy for the reaction CH4 (g) + NH3 (g) – HCN (g) + 3 H (g)....

  • What is the enthalpy of the following reaction: CH4(g) + NH3(g) à HCN(g) + 3H2(g) Use...

    What is the enthalpy of the following reaction: CH4(g) + NH3(g) à HCN(g) + 3H2(g) Use the data from the following three reactions:             N2(g) + 3H2(g) à 2NH3(g)                               DrH° = -91.8 kJ             C(s) + 2H2(g) à CH4(g)                                    DrH° = -74.9 kJ             H2(g) + 2C(s) + N2(g) à 2HCN(g)                     DrH° = +270.3 kJ 437 kJ 150 kJ 391 kJ 287 kJ 256 kJ

  • Given the following data for heats of reaction N2(g) + 3H2(g) ----> 2NH3(g)  H = -91.8 kJ...

    Given the following data for heats of reaction N2(g) + 3H2(g) ----> 2NH3(g)  H = -91.8 kJ C(graphite) + 2H2(g) -------> CH4(g)H = -74.9kJ H2(g) + 2C(graphite) + N2(g) --------> 2HCN(g)  H = 270.3 kJ Calculate H for the reaction used to make HCN CH4(g) + NH3(g) --------> HCN(g) + 3H2(g)

  • Experiment 13-Post-Lab Assignment 1. Athletes use cold packs containing ammonium nitrate solutions to ice their injuries....

    Experiment 13-Post-Lab Assignment 1. Athletes use cold packs containing ammonium nitrate solutions to ice their injuries. A 1.25 G sample of ammonium nitrate is dissolved in 25.0 mL of water to form a solution. The temperature of the solution falls from 25.8°C to 21.9°C. Find the enthalpy of the reaction (AH ), in kJ/mol. Assume the density of water is 1.00 g/mL and the heat capacity of the total solution to be 4.184 J/g °C 2. Calculate AHⓇ in kJ/mol...

  • Submit Question 33 of 50 For the chemical reaction H2 (g)+ F2 (g) 2 HF (g)...

    Submit Question 33 of 50 For the chemical reaction H2 (g)+ F2 (g) 2 HF (g) AH = -79.2 kJ/mol. What is the enthalpy for the reaction 3 H2 (g)+3 F2 (g) 6 HF (g) kJ/mol 1 2 3 4 5 6 C 8 +- 0 x 100 O 7

  • Question 34 of 50 Submit Using the equations Si(S) + 2Cl2 (9) - SICI. (S) AH...

    Question 34 of 50 Submit Using the equations Si(S) + 2Cl2 (9) - SICI. (S) AH = -640.1 kJ/mol 2 Fe (s) + 3 Cl2 (g) - 2 FeCl (s) AH = -800.0 kJ/mol Determine the enthalpy for the reaction 3 SICIA (S) + 4 Fe (s) – 4 FeCl, (s) + 3 Si (S) kJ/mol 1 2 3 C +/- : 0 x 100 Question 34 of 50 Submit Using the equations Si(S) + 2Cl2 (9) - SICI. (S)...

  • Question 8 of 20 Using the equations H2(g) + F2 (g) → 2 HF (g) AH°...

    Question 8 of 20 Using the equations H2(g) + F2 (g) → 2 HF (g) AH° = -79.2 kJ/mol C(s) + 2 F2 (g) → CF. (g) AH° = 141.3 kJ/mol 2 C(s) + 2 H2 (9) C2H4 (9) AH = -97.6 kJ/mol Determine the enthalpy for the reaction C2H4 (g) + 6 F2 (g) → 2 CF4 (9) + 4 HF (g). kJ/mol

  • Hydrogen cyanide can be prepared by reacting of methane, CH4, with ammonia by the following reaction....

    Hydrogen cyanide can be prepared by reacting of methane, CH4, with ammonia by the following reaction. CH4(g) + NH3(g) →HCN(g) +3H2(g) What is the heat of reaction at constant pressure?  Express your answer in kJ Useful information: N2(g) +3H2(g) → 2NH3(g); ΔH = -91.8 kJ C(graphite) +2H2(g) → CH4(g); ΔH = -74.9 kJ H2(g) +2C(graphite) +N2(g) → 2HCN(g); ΔH = 270.3 kJ

  • Use the following equations N2 (g) + 3 H2 (g) 2 NH3 (g) N2 (g) +...

    Use the following equations N2 (g) + 3 H2 (g) 2 NH3 (g) N2 (g) + O2 (g) → 2 NO (g) 2 H2 (g) + O2 (g) + 2 H20 (1) DH = -99.22 kJ DH = + 180.5 kJ DH = - 571.6 kJ to calculate the enthalpy change for the reaction 4 NH3 (g) + 5 O2 (g) → 4 NO (g) + 6 H20 (1) DH = ?

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT