Question

1. The compound PASy is used in matches. It reacts with oxygen to produce P4010 and SO2. The unbalanced chemical equation is shown below. P1S3(s) + O2(8) - P4010(s) + SO2(g) P.37 20 What mass of SO, is produced from the combustion of 0.401 g P S3? Pusov

Answer 1

P4S3(s) + O2(g) —> P4O10(s) + SO2(g)

Balance S:

P4S3(s) + O2(g) —> P4O10(s) + 3 SO2(g)

Balance O:

P4S3(s) + 8 O2(g) —> P4O10(s) + 3 SO2(g)

This is balanced equation

Molar mass of P4S3,

MM = 4*MM(P) + 3*MM(S)

= 4*30.97 + 3*32.07

= 220.09 g/mol

mass of P4S3 = 0.401 g

mol of P4S3 = (mass)/(molar mass)

= 0.401/2.201*10^2

= 1.822*10^-3 mol

Balanced chemical equation is:

P4S3(s) + 8 O2(g) —> P4O10(s) + 3 SO2(g)

According to balanced equation

mol of SO2 formed = (3/1)* moles of P4S3

= (3/1)*1.822*10^-3

= 5.466*10^-3 mol

Molar mass of SO2,

MM = 1*MM(S) + 2*MM(O)

= 1*32.07 + 2*16.0

= 64.07 g/mol

mass of SO2 = number of mol * molar mass

= 5.466*10^-3*64.07

= 0.3502 g

Answer: 0.350 g