Lets number the reaction as 1, 2, 3, 4 from top to bottom
required reaction should be written in terms of other reaction
This is Hess Law
required reaction can be written as:
reaction 4 = -2 * (reaction 1) +2 * (reaction 2) +3 * (reaction 3)
So, ΔHo rxn for required reaction will be:
ΔHo rxn = -2 * ΔHo rxn(reaction 1) +2 * ΔHo rxn(reaction 2) +3 * ΔHo rxn(reaction 3)
= -2 * (-310.0) +2 * (-130.0) +3 * (-220.0)
= -300 KJ
Answer: -300 KJ
ment Score: 767/2000 Resources Hint Che Question 15 of 20 > Given the thermochemical equations X,...
Given the thermochemical equations X, +3Y, 2XY, AH = -320 kJ X+2Z 2XZ AH = -160 kj 2 Y2 + Z2 2Y, Z AH, = -270 kJ Calculate the change in enthalpy for the reaction. 4XY, +72, 6Y Z + 4 XZ, AH = KJ
V Hint Check Answer < Question 20 of 27 > Given the thermochemical equations A(g) B(g) AH = 80 kJ B(g) (g) AH = -150 kJ find the enthalpy changes for each reaction. 3 A(g) — 3B(g) AH B(g) A(g)
Given the thermochemical equations X 2 + 3 Y 2⟶ 2 XY3 Δ H 1 = − 330 kJ X 2 + 2 Z2 ⟶ 2 XZ2 Δ H 2 = − 130 kJ 2 Y2 + Z2 ⟶ 2 Y2 Z Δ H 3 = − 250 kJ Calculate the change in enthalpy for the reaction. 4 XY3 + 7 Z2 ⟶ 6 Y2 Z + 4 XZ2 Δ H = kJ
erment Score: 1167/2000 Resources Hint Check Question 20 of 20 > Consider these reactions, where M represents a generic metal. 2 M(S) + 6 HCl(aq) - 2 MCI, (aq) + 3H, () AH = -646.0 kJ 2. AH = -74.81 HC (9) --- HCl(aq) H.(g) + C1,(8) -- 2 HCI(g) 3. AH; = -1845.0 MCI,() --- MCI, (aq) AH, = -273.00 Use the given information to determine the enthalpy of the reaction 2 M() + 3 C1,(B) -- 2 MCI,(s)