Given the thermochemical equations X, +3Y, 2XY, AH = -320 kJ X+2Z 2XZ AH = -160...

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science chemistry

Answer 1

Answer #1

介 Xz+372 → 2XY 2xY3 4H, = -320 KJ (2) 4H2 = -160 kj 3 X₂ +222 2x22 242 +22 → 27,2 4Hz = -270 KJ. To get the final eqh 4xY3+72

Answer 2

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