Given the thermochemical equations X2+3Y2⟶2XY3ΔH1=−380 kJ ' X2+2Z2⟶2XZ2ΔH2=−180 kJ 2Y2+Z2⟶2Y2ZΔH3=−250 kJ Calculate the change in enthalpy...

Question

Question

Given the thermochemical equations

X2+3Y2⟶2XY3ΔH1=−380 kJ '

X2+2Z2⟶2XZ2ΔH2=−180 kJ

2Y2+Z2⟶2Y2ZΔH3=−250 kJ

Calculate the change in enthalpy for the reaction. 4XY3+7Z2⟶6Y2Z+4XZ2

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Answer 1

Answer #1

Answer 2

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