Question

Suppose that you have appeared for an examination which requires you to answer questions. In your previous attempts, you answered 26% of the questions correctly a) What is the probability that you attempt none of the questions correctly? b) What is the probability that you attempt no more than two questions correct? What is the probability that you attempt at least four questions comedy? a) The probability of you answering none of the questions correctly is (Round your answer to four decimal places as needed) b) The probability of you answering not more than two questions is Round your answer to four decimal places as needed) c) The probability that you answer at least four questions correctly is Round your answer to four decimal places as needed) er your answer in each of them wer boxes

Answer 1

Here we see that n=6 is constant, p=0.25 is same for all, events are constant and only two outcomes

Hence all the properties of binomial are satisfied

So we will use binomial distribution to find required probability

a. $P(x=0)=BINOMDIST(0,6,0.26,0)=0.1642$

b. $P(x\leq 2)=BINOMDIST(2,6,0.26,1)=0.8144$

c. $P(x\geq4)=1-P(x<4)=1-P(x\leq3)=1-BINOMDIST(3,6,0.26,1)=1-0.9569=0.0431$