Question

XeO3 + __NaOH(aq) + O3 ---> 4Na^+ + XeO6^4- + __ + __H2O

Please help find the missing part of this reaction, I believe it to just be OH- but am unsure, as well as the mechanisms for the reaction.

Complete the 3 Lewis dot structures for O, below. Add Ione pairs and atomic charges where needed. (Multiple bonds have been added already.) The first two structures are resonance forms. The third is a 50/50 blend of the first two mo Now comes a hard part. What is the oxidation state of the middle O-atom on the 3 structure above? + What is the oxidation state of the end O-atoms in that 3d structure? - (Hint: The end o atoms oxidation state is different from the middle one, but neither is zero!) Now we're ready to balance the redox reaction. To the equation below. first add the product that comes from Os, and then add the correct coefficients in front of the NaOH and the H,O species XeO3 + NaOH(aq) +03 → 4Na+ + XeO4 + OH+ H2O Now comes a harder part. On the next page, write a reasonable mechanism for your balanced redox reaction. Use only nucleophilic/electrophilic steps, even though there may actually be some single electron transfer steps involved. Hint: The following two mechanistic steps from alkene ozonolysis may give you some guidance. HỌC CH, HẠC CH . and H yath Meij heyyah Lood S-CH HC Now comes the hardest part. What additional chemical reaction needs to occur in order to reach Rogers' Equation 19.20? (*That equation is correct, but it does not reveal all that is going on.)

Answer 1

Xeo₂ + 4 NaOH(aq) + O₂ 4Nah + Xeo" + O2 + 2H₂O In product, given y Nat and xeoer so, reactant and Product - both are charge balanced. so, the missing part of should be t show a neutral molecule i.e. O2 As y Not in product, co-efficient of NaOH is 4. AS 4H is in the reactant, acoesficient of H₂O is a Now, two remaining oxygen of reactant is balone by a 2 in the product.