Question

CO32−(aq)+H2O(l)←−→HCO3−(aq)+OH−(aq)

acid (proton donor)  CO32−, base (proton acceptor) H2O

acid (proton donor) H2O, base (proton acceptor) CO2−3

Part B

NH3(aq)+H2O(l)←−→NH4+(aq)+OH−(aq)

acid (proton donor)  H2O, base (proton acceptor) NH3

acid (proton donor) NH3, base (proton acceptor) H2O

Answer 1

part A

CO3- (aq) + H20 (1) HCO3- (aq) + OH (aq) CO3- (aq) + HOH (1) HCO3(aq) + OH(aq)

Here water molecule is donating a H⁺ ion to the carbonate ion, therefore,

water is the acid (proton donor) and CO₃^2- is the base ( proton acceptor).

second option is correct.

part B

NH3 (aq) + H2O (1) NH4+ (aq) + OH(aq) NH3(aq) + HOH (1) NH4+ (aq) + OH(aq)

Here again, the water molecule is providing the H⁺ ion for ammonia to form ammonium molecule. Therefore, Ammonia is the base (proton acceptor) and water is the acid ( proton donor).

first option is correct.